3 Profit, Loss and Discount
3.1 Introduction
This chapter develops a comprehensive toolkit for profit–loss–discount (PLD) questions.
We will cover:
- Core definitions and percentage measures
- Quick ratio forms and multiplier models
- Markup and discount combinations
- Successive changes and equivalent discount
- Break-even and target profit
- Mixtures of items, free/defective articles
- Taxes, overheads, depreciation
- Solved examples, traps, and practice sets
3.2 Core Definitions
- Cost Price (CP): Cost of acquiring/producing the article.
- Selling Price (SP): Price at which it is sold.
- Marked Price (MP): Printed/list price before discount.
- Discount (D): Reduction on MP.
- Profit (Gain): \(SP-CP\) (if positive).
- Loss: \(CP-SP\) (if positive).
3.2.1 Percentage Measures
Profit% (on CP):
\[ \frac{SP-CP}{CP}\times100 \]Loss% (on CP):
\[ \frac{CP-SP}{CP}\times100 \]Discount% (on MP):
\[ \frac{MP-SP}{MP}\times100 \]
Always check the base. Exam traps often hinge on CP vs MP.
3.3 Quick Ratio and Multiplier Forms
- Profit situation: \(SP=CP(1+p/100)\)
- Loss situation: \(SP=CP(1-\ell/100)\)
- Discount situation: \(SP=MP(1-d/100)\)
Reverse:
- \(CP=\tfrac{SP}{1+p/100}\) or \(\tfrac{SP}{1-\ell/100}\)
- \(MP=\tfrac{SP}{1-d/100}\)
Thumb rule: Convert every sentence to a multiplier on the correct base.
3.4 Markup and Discount Together
If markup = \(m\%\) on CP and discount = \(d\%\) on MP:
\[
SP=CP(1+m/100)(1-d/100)
\]
Effective profit%:
\[
\big[(1+m/100)(1-d/100)-1\big]\times100
\]
Example: Markup 25%, discount 20%.
SP = \(CP\times1.25\times0.8=CP\). → No profit, no loss.
3.5 Successive Percentage Changes
If two changes \(x\%\) and \(y\%\):
\[
\text{Net \%} = x+y+\frac{xy}{100}
\]
Example: Two successive discounts of 20% and 15%.
Net discount = \(20+15-3=32\%\).
3.6 Equivalent Discount
- Two discounts \(a\%\) and \(b\%\):
\[ d_{eq}=a+b-\frac{ab}{100} \]
- Three discounts \(a\%,b\%,c\%\):
\[ d_{eq}=1-(1-a/100)(1-b/100)(1-c/100) \]
3.7 Linking Markup, Discount, Profit
If markup = \(m\%\) and discount = \(d\%\):
\[
(1+m/100)(1-d/100)=1+p/100
\]
Solve for required profit \(p\) or markup \(m\).
3.8 Break-even and Margin
- Break-even: SP=CP.
- Profit margin on SP:
\[ \frac{SP-CP}{SP}\times100 \]
- To achieve target profit \(p\%\), set \(SP=CP(1+p/100)\).
3.9 Mixtures and Weighted CP
For items with costs \(c_1,c_2,\dots,c_n\):
Overall profit%:
\[
\frac{S-\sum c_i}{\sum c_i}\times100
\]
If sold at same SP per item: use average CP.
3.10 Free and Defective Articles
Buy \(x\), get \(y\) free ⇒ effective discount:
\[ \frac{y}{x+y}\times100 \]If \(k\%\) defective: profit% falls since fewer items are saleable.
Example: 100 pens at cost 10 each. 10% defective. Desired profit=20%.
CP=1000. Revenue target=1200. Good pens=90. SP per pen=1200/90=13.33.
3.11 Taxes, Overheads, Depreciation
- With GST \(t\%\): Billed price = \(SP(1+t/100)\).
- Overheads: add before computing profit.
- Depreciation: Value after \(n\) years at \(d\%\):
\[ V=V_0(1-d/100)^n \]
3.12 Solved Examples
Article sold at 690 after 23% discount. MP?
\(690/0.77=896.10\).Markup needed for 25% profit after 20% discount?
\((1+m)(0.8)=1.25\) → \(m=56.25\%\).Successive discounts 30% and 10% on 500.
SP=500×0.7×0.9=315. Net discount=37%.Buy 4 get 1 free. Effective discount=20%.
200 bulbs @30 each, 10% defective. Profit 25% overall.
CP=6000. Revenue=7500. Good bulbs=180. SP=7500/180=41.67.Item sold at 10% loss. If SP increased by 63, profit=5%. Find CP.
Let CP=x. 0.9x+63=1.05x → x=420.Profit is 25% of SP. Find profit% on CP.
SP=100, profit=25, CP=75. Profit%=25/75×100=33.33%.Article listed at 2000, discount 10%, GST 18%.
SP=1800. Bill=1800×1.18=2124.
3.13 Common Traps
- Wrong base (CP vs SP vs MP).
- Adding discounts linearly.
- Freebies change quantity base, not tag price.
- Margin vs profit confusion.
- Always check with CP=100 for quick sanity.
3.14 Practice Set – Level 1
- CP=640, profit=12.5%. Find SP.
- SP=750, loss=20%. Find CP.
- MP=1200, discount 25%. Find SP and discount.
- Successive discounts 10% and 15% on 2000. Find SP and net discount.
- Markup 40%, discount 30%. Find effective profit%.
3.15 Practice Set – Level 2
- To earn 30% profit after 20% discount, find markup%.
- Trader sells at 15% profit but gives 1 in 10 free. Effective profit%?
- Tea mix: 2 kg at 200, 3 kg at 300. Mixture sold at 280/kg. Profit%?
- Machine depreciates 10% annually. Value after 3 yrs is 14580. Find initial.
- Goods marked 60% above CP. To earn 20% profit, what discount?
3.16 Practice Set – Level 3
- Two successive equal discounts \(a\%\) result in 51% of MP. Find \(a\).
- Dealer sells two items at same SP, one 25% gain, other 20% loss. Net result?
- Dishonest dealer: 900 g weight, 10% discount, CP=100/kg, MP=150. Effective profit%?
- Watch sold at 10% loss. If bought 10% less and sold 27 more, profit=20%. Find CP.
- Article with MP=P. Discounts 10%, 20%, 25% lead to SP=972. Find P.
3.17 Answer Key (Outline)
Level 1: 1) 720; 2) 937.5; 3) SP=900, D=300; 4) SP=1530, net=23.5%; 5) -2%.
Level 2: 6) 62.5%; 7) ≈6.11%; 8) 4%; 9) 20000; 10) 25%.
Level 3: 11) 30%; 12) 2% loss; 13) 23.33% profit; 14) 750; 15) 1800.
3.18 Summary
- Translate words → multipliers.
- Successive % changes: use formula or chained multipliers.
- Free/defective items: adjust quantity base.
- Differentiate margin on SP vs profit on CP.
- Most PLD problems reduce to 2–3 clean multiplier steps.